If `A=[alphabetagamma-alpha]` is such that `A^2=I` , then `1+alpha^2+betagamma=0` (b) `1-alpha^2+betagamma=0` (c) `1-alpha^2-betagamma=0` (d) `1+alpha^2-betagamma=0`

Explanation

To solve the problem, we need to analyze the given matrix \( A \) and the condition \( A^2 = I \), where \( I \) is the identity matrix. The matrix \( A \) is defined as:

\[ A = \begin{bmatrix} \alpha & \beta \\ \gamma & -\alpha \end{bmatrix} \]
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