If a square matrix such that `A^2=A` , then `(I+A)^3-7A` is equal to `A` (b) `I-A` (c) `I` (d) `3A`

Explanation

To solve the problem, we need to evaluate the expression \((I + A)^3 - 7A\) given that \(A^2 = A\).

### Step-by-Step Solution:

1. **Understanding the Property of Matrix A**:
Since \(A^2 = A\), we can conclude that \(A\) is an idempotent matrix. This means that multiplying \(A\) by itself yields \(A\).

2. **Finding \(A^3\)**:
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