If `A` is a square matrix such that `A^2=I` , then `(A-I)^3+(A+I)^3-7A` is equal to `A` (b) `I-A` (c) `I+A` (d) `3A`

Explanation

To solve the problem, we need to evaluate the expression \((A-I)^3 + (A+I)^3 - 7A\) given that \(A^2 = I\).

### Step-by-Step Solution:

1. **Understanding the Given Condition**:
Since \(A^2 = I\), we know that \(A\) is an involutory matrix. This means that \(A\) is its own inverse, i.e., \(A^{-1} = A\).

2. **Calculating \(A^3\)**:
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