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If `A` and `B` are matrices of the same order, then `A B^T-B A^T` is a (a) skew-symmetric matrix (b) null matrix (c) unit matrix (d) symmetric matrix

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We have given:`A` and `B` are matrices of the same order
Then we have to find `A B^T-B A^T`
Take `(A B^T-B A^T)^T=(AB^T)^T-(BA^T)^T`
`=BA^T-AB^T`
`=-(AB^T-BA^T)`
...
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