Without expanding evaluate the determinant `|41 1 5 79 7 9 29 5 3|` .

Answer

Determinant `=0`

Explanation

We know that `C_{1} \Rightarrow C_{1}-C_{2}`, would not change anything for the determinant.


Applying the same in above determinant, we get


$$ [\begin{array}{lll}41 & 1 & 5 \\ 79 & 7 & 9 \\ 29 & 5 & 3\end{array}] $$
Now it can clearly be seen that `C_{1}=8 \times C_{3} - C_{2}`

Applying above equation we get,
$$
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