[ff(x)=(x-1)/(2x^(2)-7x+5)+tan x!=f(x)=(-1)/(3)],[tan x=1tan f'(1)=]

The range of f(x)=(1-tan x)/(1+tan x) is

The range of f(x)=(1-tan x)/(1+tan x) is

The function f(x)=tan^(-1)(tan x) is

If f(x) =tan ^(-1)x-(1)/(2)log x . Then -

f((2tan x)/(1+tan^(2)x))=((cos2x+1)(sec^(2)x+tan x))/(2) then f(x)=

If f(x)=tan^(-1)x-(1)/(2)log x. Then

Find the sum of each of the following series: (i) tan^(-1)((1)/(x^(2)+x+1))+tan^(-1)((1)/(x^(2)+3x+3))+tan^(-1)((1)/(x^(2)+5X+7))+tan^(-1)((1)/(x^(2))+7x+13))...... upto n.

Let |{:(tan^(-1)x, tan^(-1)2x, tan^(-1)3x), (tan^(-1)3x, tan^(-1)x, tan^(-1)2x), (tan^(-1)2x, tan^(-1)3x, tan^(-1)x):}|=0 , then the number of values of x satisfying the equation is

f((2tan x)/(1+tan^(2)x))=((cos2x+1)(sec^(2)x+2tan x))/(2) then f((1)/(4))=