Using properties of determinants, solve the following for x: `|x-2 2x-3 3x-4x-4 2x-9 3x-16 x-8 2x-27 3x-64|=0`

Answer

`x=4`

Explanation

Given,
$$
\begin{aligned}
&\left|\begin{array}{ccc}
x-2 & 2 x-3 & 3 x-4 \\
x-4 & 2 x-9 & 3 x-16 \\
x-8 & 2 x-27 & 3 x-64
\end{array}\right|=0 \\ \\
...