Solve the following system of the linear equations by cramer's rule `3x+y+z=2 ,2x-4y+3z=-1 and 4x+y-3z=-11`

Explanation

We have given:`3x+y+z=2 ,2x-4y+3z=-1 and 4x+y-3z=-11`

As we know that the system of linear equation can be written in matrix form as `AX = B`

`implies A=|(3,1,1),(2,-4,3),(4,1,-3)|`,`X=[(x),(y),(z)]`,`B=[(2),(-1),(-11)]`

Now find the determinant of `A`,

`|A|= |(3,1,1),(2,-4,3),(4,1,-3)|`

`|A|=3(12−3)-1(-6-12)+1(2+16)`

`|A|=27+18+18`

`|A|=Delta=63`

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