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If |[2x,x+3 ],[2(x+1),x+1]|=|[1, 5],[ 3 ...

If `|[2x,x+3 ],[2(x+1),x+1]|=|[1, 5],[ 3 ,5]|` , then write the value of `xdot`

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Given,`|[2x,x+3 ],[2(x+1),x+1]|=|[1, 5],[ 3 ,5]|`
Solving both sides
=`2x(x+1)-2(x+3)(x+1)=3-15`
=`2x^2-2x-2x^2-8x-6=-12`
=`-6x-6=-12`
or `x=1`
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