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If x in N and |x+3-2-3x2x|=8, then find ...

If `x in N` and `|x+3-2-3x2x|=8,` then find the value of `xdot`

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Solving the above matrix we get :
` (x+3)(2x)−(−3x)(−2)=8`
`therefore 2x^2+6x−6x=8`
`2x^2=8`
`x^2=28​=4`
`x=4`​
`x=pm2`
since `xinN` we have `x=2`
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