If `A`
is an square matrix of
order `3`
such that `|A|=2`
, then write the value
of `|a d j (a d j A)|`
.
Text Solution
Verified by Experts
We know that`|adj(A)|=|A|^(n-1)`
`|adjadj(A)|=|adjA|^(n-1)`
=`(|A|^(n-1))^(n-1)`
Since the order of matrix is 3 or n=3
`|adjadj(A)|=(2^(3-1))^(3-1)=16`
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