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If A=[cosalpha-sinalpha0sinalphacosalpha...

If `A=[cosalpha-sinalpha0sinalphacosalpha0 0 0 1]` , find `a d j\ A` and verify that `A(a d j\ A)=(a d j\ A)A=|A|I_3` .

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`A=[[cos alpha, -sin alpha, 0], [sin alpha , cos alpha , 0], [0, 0 , 1]]`
`|A| =0-0+1(cos ^{2} alpha+sin ^{2} alpha) =1`
`a_{11}=cos alpha` ...
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