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If A=[[-1,2,0],[-1,1,1],[0,1,0]] , show ...

If `A=[[-1,2,0],[-1,1,1],[0,1,0]]` , show that `A^(-1)=A^2` .

Text Solution

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`A=[[-1,2,0],[-1,1,1],[0,1,0]]`
here `|A|=1!=0 ` thus `A^(-1)` exists
So,
`A^2=AxxA`
`=>[[-1,2,0],[-1,1,1],[0,1,0]][[-1,2,0],[-1,1,1],[0,1,0]]`
...
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