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Find the inverse following matrix and verify that `A^(-1)A=I_3` . `[1 3 3 1 4 3 1 3 4]`

Text Solution

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`A=[[1, 3, 3], [1, 4, 3], [1, 3, 4]]`
`|A|=1`
`adj A=[[7, -3, -3], [-1, 1, 0], [-1, 0, 1]]`
`A^(-1)=[[7, -3, -3], [-1, 1, 0], [-1, 0, 1]]`
`A^(-1) A=[[7, -3, -3], [-1, 1, 0], [-1, 0, 1]] [[1, 3, 3], [1, 4, 3], [1, 3, 4]]`
`=[[1, 0, 0], [0, 1, 0], [0, 0, 1]]`
`=I_3`
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