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Show that A=[[5, 3], [-1, -2]] satisfies...

Show that `A=[[5, 3], [-1, -2]]` satisfies the equation `x^2-3x-7=0` . Thus, find `A^(-1)`

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`A=[[5, 3], [-1, -2]]`
`A^2=[[5, 3], [-1, -2]] [[5, 3], [-1, -2]]`
`=[[22, 9], [-3, 1]]`
`3A=[[15, 9],[-3, -6]]`
`7I=[[7,0],[0,7]]`
`A ^2 −3A−7I=[[0,0],[0,0]]` ...
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