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Using elementary row transformation find the inverse of the matrix `A=[3 -1 -2 2 0 -1 3 -5 0]`

Text Solution

Verified by Experts

Given,
`A=[(3,-1,2),(2,0,-1),(3,-5,0)]`
we know that,
`AA^(-1)=I`
So,
`[(3,-1,2),(2,0,-1),(3,-5,0)]=[(1,0,0),(0,1,0),(0,0,1)]A`
Applying `R1->R1-R2`
...
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