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Find the inverse using elementary row ...

Find the inverse using elementary row transformations: `[7 1 4-3]`

Text Solution

Verified by Experts

(i)We know that,
`A``A^(-1)=I`
So,
`[(7,1),(4,-3)]A^(-1)=[(1,0),(0,1)]`
Applying `r1=1/7r1` and `r=r2-4r1`
`[(1,1/7),(0,-(25)/7)]A^(-1)=[(1/7,0),(-4/7,1)]`
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