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Find the inverse using elementary row...

Find the inverse using elementary row transformations: `[2 0-1 5 1 0 0 1 3]`

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A=`[(2, 0,-1), (5 ,1 ,0), (0, 1, 3)]`
We know that,
`A=IA`
`[(2, 0,-1), (5 ,1 ,0), (0, 1, 3)]`=`[(1, 0,0), ( 0,1 ,0), (0, 0, 1)]A`
Applying `r1=1/2r1` and `r2=r2-5r1`
So,
`[(1, 0,-1/2), (0 ,1 ,5/2), (0, 1, 1/2)]`=`[(1/2, 0,0), ( -5/2,1 ,0), (0, 0, 1)]A` ...
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