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Find the inverse using elementary row...

Find the inverse using elementary row transformations: `[2 3 1 2 4 1 3 7 2]`

Text Solution

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A=`[(2, 3 ,1),( 2, 4 ,1),( 3, 7 ,2)]`
We know that,
`A=IA`
`[(2, 3 ,1),( 2, 4 ,1),( 3, 7 ,2)]`=`[(1, 0 ,0),( 0, 1 ,0),( 0, 0 ,1)]A`
Applying `r1=1/2r1` and `r2=r2-2r1` and `r3=r3-3r1`
`[(1, 3/2 ,1/2),( 0, 4 ,1),( 0, 5/2,1/2)]`=`[(1/2, 0 ,0),( -1, 1 ,0),( -3/2, 0 ,1)]A`
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