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Find the inverse using elementary row...

Find the inverse using elementary row transformations: `[3-3 4 2-3 4 0-1 1]`

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A=`[(3,-3, 4),( 2,-3 ,4),( 0,-1 ,1)]`
`A=IA`
So,
`[(3,-3, 4),( 2,-3 ,4),( 0,-1 ,1)]`=`[(1,0, 0),( 0,0 ,1),( 0,0 ,1)]A`
applying `r1=1/3r1` and `r2=r2-2r1`
we get,
`[(1,-1, 4/3),( 0,1 ,-4/3),( 0,-1 ,1)]`=`[(1/3,0, 0),( 2/3,-1 ,0),( 0,0 ,1)]A`
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