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Find the inverse using elementary row...

Find the inverse using elementary row transformations: `[1 2 0 2 3-1 1-1 3]`

Text Solution

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A=`[(1, 2, 0),( 2, 3,-1),( 1,-1, 3)]`
`A=IA`
So,
`[(1, 2, 0),( 0, 1,1),( 0,-3, 3)]`=`[(1, 0, 0),( 0, 1,0),( 0,0, 1)]A`
`R2​→2R1​−R2​`
`R3​→R3​−R1​`
`[(1, 2, 0),( 2, 3,-1),( 1,-1, 3)]`= ...
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