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Use elementary column operation on applying `C_2 ->C_2+2C_1`
in the following matrix equation : `[(2 ,1),( 2, 0)]=[(3, 1),( 2, 0)][(1, 0),(-1, 1)]`

Text Solution

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Given, `[(2 ,1),( 2, 0)]=[(3, 1),( 2, 0)][(1, 0),(-1, 1)]` on applying `C_2 ->C_2+2C_1`
`[(2 ,1+4),( 2, 0+4)]=[(3, 1),( 2, 0)][(1, 0+2),(-1, 1+2)]`
`[(2 ,5),( 2, 4)]=[(3, 1),( 2, 0)][(1 ,2),(-1, -1)]`
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