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If A=[(1, 2,-1),(-1, 1, 2),( 2,-1, 1)] ,...

If `A=[(1, 2,-1),(-1, 1, 2),( 2,-1, 1)]` , then `det(a d j\ (a d j\ A))` is `14^4` (b) `14^3` (c) `14^2` (d) 14

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We have, `A=[(1, 2,-1),(-1, 1, 2),( 2,-1, 1)]`
`∣A∣=1(1+2)−2(−1−4)−1(1−2)`
=`3+10+1=14`
We know that, for a square matrix of order n,
`adj(adjA)=∣A∣^(n−2)A, if ∣A∣!=0`
`det(adj(adjA))=∣∣A∣^(n−2)A∣ `
...
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