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For non-singular square matrix `A ,\ B\ a n d\ C` of the same order `(A B^(-1)C)^(-1)=` `A^(-1)B C^(-1)` (b) `C^(-1)B^(-1)A^(-1)` (c) `C B A^(-1)` (d) `C^(-1)\ B\ A^(-1)`

Text Solution

Verified by Experts

We have given three non-singular square matrix `A ,\ B\ a n d\ C`
Then we have to find `(A B^(-1)C)^(-1)`
As we have
`(AB^(-1)C)^(-1)=C^(-1)(B^(-1))^(-1)A^(-1)`
`implies (AB^(-1)C)^(-1)=C^(-1)BA^(-1)`
Hence correct option is (d).
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