If A is a square matrix such that `A^2 = I`, then `A^(-1)` is equal to
(i) I
(ii) 0
(iii) A
(iv) I+A
Text Solution
Verified by Experts
We have given that A is a square matrix such that `A^2 = I`
then we have to find `A^(-1)`
As `A^2=I`
`A.A=I`
Post multiplying by `A^(−1)`
both the sides
`A.(A``A^(−1)=I.A^(−1)`
`AI=IA^(−1)`
...
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