Using matrix method, solve the following system of linear equations. `3x+4y+2z=8, 2y-3z=3 and x-2y+6z=-2`

Explanation

We have given:`3x+4y+2z=8, 2y-3z=3 and x-2y+6z=-2`

As we know that the system of linear equation can be written in matrix form as `AX = B`

`implies A=|(3,4,2),(0,2,-3),(1,-2,6)|`,`X=[(x),(y),(z)]`,`B=[(8),(3),(-2)]`

Now find the determinant of `A`,

`|A|= |(3,4,2),(0,2,-3),(1,-2,6)|`

`|A|=3(12−6)−4(0+3)+2(0−2)`

`|A|=3(6)−4(+3)+2(−2)`

`|A|=2`

...