Using matrix method, solve the following system of equations: `2/x+3/y+(10)/z=4,4/x-6/y+5/z=1,6/x+9/y-(20)/z=2; x ,\ y ,\ z\ !=0`

Explanation

We have given:`2/x+3/y+(10)/z=4,4/x-6/y+5/z=1,6/x+9/y-(20)/z=2`

Now take `1/x=p,1/y=q,1/z=r`

Then

`2p+3q+10r=4`,

`4p−6q+5r=1`,

`6p+9q−20r=2`

As we know that the system of linear equation can be written in matrix form as `AX = B`

`implies A=|(2,3,10),(4,-6,5),(6,9,-20)|`,`X=[(p),(q),(r)]`,`B=[(4),(1),(2)]`

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