If `A\|(1,2,0),(-2,-1,-2),(0,-1,1)|`, then find the value of `A^(-1)`
Using `A^(-1)`, solve the system of linear equations `x-2y=10, 2xy-z=8` and `-2y+z=7`

Explanation

We have, $$A=\left[\begin{array}{ccc}1 & 2 & 0 \\ -2 & -1 & -2 \\ 0 & -1 & 1\end{array}\right] \ldots($$ i)
$$ \therefore|A|=1(-3)-2(-2)+0=1 \equiv 0 $$
Now,$$A_{11}=-3, A_{12}=2, A_{13}=2, A_{21}=-2, A_{22}=1, A_{23}=1, A_{31}=-4, A_{32}=2$$ and $$A_{33}=3$$
$$
\therefore \operatorname{adj}(A)=\left|\begin{array}{ccc}
-3 & 2 & 2 \\
...