The system of equations: `x+y+z=5` `x+2y+3z=9` `x+3y+lambdaz=mu` has a unique solution, if `lambda=5,mu=13` (b) `lambda!=5` `lambda=5,mu!=13` (d) `mu!=13`

Explanation

Answer is B


We have equations `A X=B`


`A= [[1, 1 , 1],[ 1 , 2, 3],[ 1 , 3, lambda]], X=[ [x], [ y ],[ z]], B=[[ 5 ],[ 9], [ mu]]`



`D equiv 0`

`

Rightarrow[
[1, 1, 1], [1 ,2 ,3 ],[1, 3, lambda]] equiv 0`

`
...