If `f(2)=4` and `f^(prime)(2)=1` , then find `(lim)_(x->2)(x\ f(2)-2f\ (x))/(x-2)` .

Explanation

To solve the limit \( \lim_{x \to 2} \frac{x f(2) - 2f(x)}{x - 2} \), we can follow these steps:

### Step 1: Substitute the known values
We know that \( f(2) = 4 \). Therefore, we can substitute this value into the limit expression:

\[ \lim_{x \to 2} \frac{x \cdot 4 - 2f(x)}{x - 2} \]
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