Show that the function `f(x)={x^msin(1/x),\ \ \ x!=0 0,\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x=0` is continuous but not differentiable at `x=0` , if `0

Explanation

To show that the function

\[
f(x) =
\begin{cases}
x^m \sin(1/x) & \text{if } x \neq 0 \\
0 & \text{if } x = 0
\end{cases}
...