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Differentiate log(secx+tanx) with respec...

Differentiate `log(secx+tanx)` with respect to `x` :

Text Solution

Verified by Experts

Given:`log(secx+tanx)`
Then
Let `y=log(secx+tanx)`
Now differentiating w.r to `x`
`(dy)/(dx)=d/(dx)(log(secx+tanx))`
`=1/(secx+tanx).(secxtanx+sec^2x)`
`=(secx(tanx+secx))/(secx+tanx)`
`(dy)/(dx)=secx`
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