Differentiate `sin^(-1)((a+bcosx)/(b+acosx)),\ b > a` with respect to `x`.

Explanation

To differentiate the function \( y = \sin^{-1}\left(\frac{a + b \cos x}{b + a \cos x}\right) \) with respect to \( x \), we will use the chain rule and the quotient rule. Here’s the step-by-step solution:

### Step 1: Identify the function to differentiate
Let:
\[ u = \frac{a + b \cos x}{b + a \cos x} \]
Then, we have:
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