Differentiate `sqrt(log{sin((x^2)/3-1)})` with respect to `x`

Explanation

Let,

`y=sqrt(log{sin((x^2)/3-1)})`

Chain rule:

`y=f[g(x)]`

`frac{dy}{dx}=f'[g(x)]*g'(x)`

Squaring both sides,

`y^2=log{sin((x^2)/3-1)}`


We know that,

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