When 1 mol `CrCl_(3).6H_(2)O` is treated with excess of `AgNO_(3)`, 3 mol of `AgCl` are obtained. The formula of the coplex is

When 1 mol CrCl_3 .6H_2O is treated with excess of AgNO_3 , 3 3 mol of AgCl are obtained. The formula of the complex is:

When 1 mole CrCl_(3).6H_(2)O is treated with excess of AgNO_(3), 3 mol AgCl are obtained. Formula of the complex :

When one mole CrCl_3 .6H_2O is treated with excess of AgNo_3 , 3 mole of AgCl is obtained. The formula of complex is

When 0.1 mol CoCl_(3)(NH_(3))_(5) is treated with excess of AgNO_(3) , 0.2 mol of AgCl are obtained. The conductivity of solution will correspound to -