Differentiate `cot^(-1)((1-x)/(1+x))` with respect to `x ` .

Explanation

Given that `y=\cot ^{-1}(\frac{1-x}{1+x})`



Let `x=\tan \theta \Rightarrow \theta=\tan ^{-1} x`



and using `\cot ^{-1} x=\frac{\pi}{2}-\tan ^{-1} X`



Hence, `y=\frac{\pi}{2}-\tan ^{-1}(\frac{1-\tan \theta}{1+\tan \theta})`



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