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If x^2+y^2=t-1/t and x^4+y^4=t^2+1/(t^2)...

If `x^2+y^2=t-1/t` and `x^4+y^4=t^2+1/(t^2)` , then prove that `(dy)/(dx)=1/(x^3y)`

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To solve the problem step-by-step, we start with the given equations: 1. **Given Equations:** \[ x^2 + y^2 = t - \frac{1}{t} \] \[ x^4 + y^4 = t^2 + \frac{1}{t^2} ...
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