If `4x+3y=log(4x-3y)` , find `(dy)/(dx)`

Explanation

$$ 4 x+3 y=\log (4 x-3 y) $$
Differentiating w.r.t. `x`, we get,
$$ 4+3 \frac{d y}{d x}=\frac{1}{4 x-3 y}\left(4-3 \frac{d y}{d x}\right) $$
$$
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