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Differentiate (sinx)^(logx) with respect...

Differentiate `(sinx)^(logx)` with respect to `x` :

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$$ y=(\sin x)^{\log x} $$ Applying log on both sides:- $$ \Rightarrow \log y=\log x \log (\sin x) $$ Now differentiating with respect to `x`, we get ...
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