If `x=e^(x//y)` , prove that `(dy)/(dx)=(x-y)/(xlogx)`

Explanation

To prove that \(\frac{dy}{dx} = \frac{x - y}{x \log x}\) given that \(x = e^{\frac{x}{y}}\), we can follow these steps:

### Step 1: Take the natural logarithm of both sides
We start with the equation:
\[ x = e^{\frac{x}{y}} \]
Taking the natural logarithm of both sides:
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