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Find (dy)/(dx): x=a(theta-sintheta) and ...

Find `(dy)/(dx):` `x=a(theta-sintheta)` and `y=a(1-costheta)`

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`x=a(theta+sintheta)`
`implies (dx)/(d theta)=a(1+costheta)... (1) `
`y=a(1-cos theta)`
`implies(dy)/(d theta)=a(0-(-sin theta))=a sin theta....(2) `
Dividing (2) and (1) we get,
`(dy//d theta)/(dx//d theta)`
`=(dy)/(dx)`
`=(sin theta)/(1+cos theta)`
`=tan( theta//2)`
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