If `f(x)=x+1` , then write the value of `d/(dx)(fof)(x)` .

Explanation

`text { We have }, f(x)=x+1 `

`text { Now, }(text { fof })(x)=f(f(x)) `

`Rightarrow(text { fof })(x)=f(x+1) `

`Rightarrow(text { fof })(x)=(x+1)+1`

`Rightarrow(text { fof })=x+2 `

`Rightarrow frac{d}{d x}{(text { fof })(x)}=frac{d}{d x}(x)+frac{d}{d x}(2) `

`Rightarrow frac{d}{d x}{(text { fof })(x)}=1+0`

`Rightarrow frac{d}{d x}{(text { fof })(x)}=1`