If `y=tan^(-1)((1-x)/(1+x))` , find `(dy)/(dx)` .

Explanation

To find the derivative \( \frac{dy}{dx} \) for the function \( y = \tan^{-1}\left(\frac{1-x}{1+x}\right) \), we can follow these steps:

### Step 1: Substitute \( x \) with \( \tan(\theta) \)

Let \( x = \tan(\theta) \). Then, we can express \( y \) in terms of \( \theta \):
\[ y = \tan^{-1}\left(\frac{1 - \tan(\theta)}{1 + \tan(\theta)}\right) \]
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