If `x^y=e^(x-y)` , then `(dy)/(dx)` is (a)`(1+x)/(1+logx)` (b) `(1-logx)/(1+logx)` (c) not defined (d) `(logx)/((1+logx)^2)`

Explanation

To find \(\frac{dy}{dx}\) given the equation \(x^y = e^{(x - y)}\), we will follow these steps:

### Step 1: Take the natural logarithm of both sides
We start by taking the natural logarithm of both sides of the equation:

\[ \ln(x^y) = \ln(e^{(x - y)}) \]
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