If `y=sin^(-1)((1-x^2)/(1+x^2))` , then `(dy)/(dx)=` (a)`-2/(1+x^2)` (b) `2/(1+x^2)` (c) `1/(2-x^2)` (d) `2/(2-x^2)`

Explanation

To solve the problem, we start with the given function:

\[ y = \sin^{-1}\left(\frac{1 - x^2}{1 + x^2}\right) \]

### Step 1: Substitution
We will use the substitution \( x = \tan(\theta) \). This helps simplify the expression.

### Step 2: Transform the expression
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