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If siny=xcos(a+y) , then (dy)/(dx) is eq...

If `siny=xcos(a+y)` , then `(dy)/(dx)` is equal to (a)`(cos^2(a+y))/(cosa)` (b) `(cosa)/(cos^2(a+y))` (c) `(sin^2y)/(cosa)` (d) none of these

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To find \(\frac{dy}{dx}\) given the equation \( \sin y = x \cos(a + y) \), we will use implicit differentiation. Here’s a step-by-step solution: ### Step 1: Differentiate both sides with respect to \(x\) Starting with the equation: \[ \sin y = x \cos(a + y) \] ...
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