If `y=asint` and `x=a(cost+logtant/2)` , find `(d^2y)/(dx^2)` .

Explanation

We are given,
`x=a(cost+logtan(t/2))`

and `y=asint`

Let differentiate x & y wrt t, we get,

`(dy)/(dt)=acost`

`(dx)/(dt)=a[(−sint)+1/(tan(t/2)).sec^2(t/2)(1/2)]=(a(cos^2t))/(sint)`

Now

`(dy)/(dx)=((dy)/(dt))xx((dt)/(dx))=tant`

again differentiate this wrt x

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