If `x=a(1-cos^3theta)` , `y=a\ s in^3theta` , prove that `(d^2y)/(dx^2)=(32)/(27\ a)` at `theta=pi/6` .

Explanation

`x=a(1-\cos ^{3} \theta), y=a \sin ^{3} \theta`


to prove` \frac{d^{2} y}{d x^{2}}=\frac{32}{27 a}`


at ` \theta=\frac{\pi}{6} `



`\frac{d y}{d \theta}=3 a \sin ^{2} \theta \cdot \cos \theta `
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