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If x=acosn t-bsinn t and (d^2x)/(dt^2)=l...

If `x=acosn t-bsinn t` and `(d^2x)/(dt^2)=lambdax` , then find the value of `lambda` .

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x=a cos n t-b sin n t Now,
` frac{d x}{d t}=-a n sin n t-b n cos n t `
` frac{d^{2} x}{d t^{2}}=-a n^{2} cos n t+b n^{2} sin n t`
Also,
...
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