If `x=a t^2,\ \ y=2\ a t` , then `(d^2y)/(dx^2)=` `-1/(t^2)` (b) `1/(2\ a t^3)` (c) `-1/(t^3)` (d) `-1/(2\ a t^3)`

Explanation

`x=a t^{2} and y=2 a t`

On differentiating both sides w.r.t. t, we get,
`

frac{d x}{d t}=2 a t text { and } frac{d y}{d t}=2 a`


Therefore,
`

frac{d y}{d x}=frac{2 a}{2 a t}=frac{1}{t}`

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